Solve the equation. Express radicals in simplest form.

Question

(x+6)^2 = 44

 

So I know how to do the square root property but don't know how to do it with the 44 being there (and not having a perfect square)

 

The answers Are

 

A) -6 + 2√11, -6 - 2√11

 

B) 2√11 - 6, 2√11 + 6

 

C) 2√11, - 2√11

 

D) -6 + 2√22, -6 - 2√22

Answer 1

Choice "A" is correct.

 

If (x+6) squared is 44, then (x+6) must be the square root of 44.

 

Then x must be -6 + or - the square root of 44. Since 44 equals 4 times 11 the square root of 44 is also 2 times the square root of 11.

 

Thus -6 + 2 times the square root of 11 is one correct answer and

 

        -6 - 2 times the square root of 11 is another correct answer

 

Choice "A" says the same thing