Algebra 1 intermediate

Question

Find the equation in slope-intercept form of the line that passes through the points (-2,4) and (6, 2).

Answer 1

the slope is m = (4-2)/(-2 - 6) = 2/-8 = -1/4

y = mx + b is the equation of the line.

b = y - mx

= 2- (-1/4)(6) <---- y=2 when x=6 per the SECOND POINT that is GIVEN.

= 2 + 6/4

= 2 + 3/2

=(4+3)/2

= 7/2

the equation of the line is y = (-1/4)x + 7/2

Note that , using the FIRST GIVEN POINT, y=4 when x=-2,

and per the line equation just found,

y = (-1/4)(-2) + 7/2 = 1/2 + 7/2 = 8/2 = 4 when x=-2, so (-2,4) is on the line

as given, which PROVES the answer is correct.

y = (-1/4)x + 7/2 is the equation of the line that eats the points (-2,4) and (6,2)

done deal....