Correctly seperate the absolute value equation Ix^2 - 4I = 3

Answer 1

|x^2 -4| = 3

Two Solutions to x since |3| and |-3| are both equal to 3.

x^2 -4 = 3

Isolate x

x^2 -4 +4 = 3 +4

x^2 + 0 = 7

x^2 = 7, square root both sides

(x^2)^(1/2) = 7^(1/2)

x = 7^(1/2) = 7^0.5 ~2.65

x^2 -4 = -3

isolate x

x^2 -4 +4 = -3 +4

x^2 + 0 = 1

x^2 = 1, square root both sides

(x^2)^(1/2) = 1^(1/2)

x = 1

solutions are x = 1 and ~2.65