write the equation for a line that is parallel to the line y=5-2/3x and passes through the point (-3,0).

Answer 1

Since the new line has the same slope as y = 5 - (2/3)x the new line equation is

y-0 = -(2/3)(x+3) or y = -(2/3)x -2

(I am assuming that the equation is y = 5-(2/3)x and not y = 5-2/3x

Answer 2

The slope of the parallel line is the same as the slope of the given line.

The use the point-slope form:

-2/3 = y/x+3

You can "massage" this equation into whatever form you need.