Carlos G.

asked • 12/09/14

Equation of Conics

Write the equation of the conic in standard form and indicate which conic it is 
x^2 + 4y^2 - 6x + 16y + 21=0
 
This is what I did 
 
(x^2 - 6x + 9) - 4(y^2 + 4y +4)=-21 + 9 - 4
 
(x-3)^2  -  4(y+2)^2 =-16
 
((x-3)^2/-16) - (4(y+2)^2/-16) = -16/-16
 
Don't know if this is the answer :
((x-3)^2/-16) - ((y+2)^2/-4) = 1

1 Expert Answer

By:

Linda C. answered • 12/09/14

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