Linda C. answered • 12/09/14

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New to Wyzant
Secondary Math Tutor

Is there a negative in the original problem? In front of the y squared term? Because I don't know where that came from in your solution. Also, you would need to factor out the 4 from ALL of your y terms, so when you complete that square, you would still have your (y+2), but you would have added 4*4, or 16 on the other side. You are off to a nice start.

Here's my work and solution for the original problem as written:

x

^{2}-6x+9+4(y^{2}+4y+4) = -21+9+16^{}(x-3)

^{2}+4(y+2)^{2}=4^{}**(x-3)**

^{2}/4 + (y+2)^{2}/1 = 1