Need help with my question in chemistry

Question

Calculate the ΔH of 200ml 1M HI acid mixed with 100ml 2M KOH solution?

ΔHf KI/H2O= -57.5 KJ/Mole

answers:

a - 11.5 KJ

b - 10.5 KJ

c - 12.5 KJ

d - 9.5 KJ

Thanks.

Answer 1

Balanced equation is HI(aq) + KOH(aq) ==> H2O(l) + KI(aq)

moles HI = 0.200 L x 1 mol/L = 0.200 moles

moles KOH = 0.1 L x 2 mol/L = 0.200 moles

∆H_reaction = -57.5 kJ/mole x 0.200 moles = -11.5 kJ (answer a)