
Kevin B. answered 05/02/19
Former Teacher and Math Expert
Here's one way to solve (x+4)2·(x-6) > 0:
Step 1 Solve (x+4)2·(x-6) = 0
Hopefully, solving (x+4)2·(x-6) = 0 will not be difficult. Since the left-hand side of this equation is already factored, we just need to set each factor equal to zero and solve for x.
(x + 4)2 = 0 <---> x = -4
x - 6 = 0 <---> x = 6
Step 2 With these two values x = -4 and x = 6, we divide the number line into three sections
Section 1: all values x < -4
Section 2: all values -4 < x < 6
Section 3: all values x > 6
Step 3 We now choose one test value of x for each section. If that value satisfies the inequality (x+4)2·(x-6) > 0, then that section is part of our solution. Keep in mind, any value from that section will due.
Section 1: Let x = -5. Then (-5+4)2(-5-6) = (1) (-11) is negative. NOT A SOLUTION
Section 2: Let x = 0. Then (0+4)2(0-6) = (16)(-6) is negative. NOT A SOLUTION
Section 3: Let x = 7. Then (7+4)2(7-6) = (112)(1) is positive. SOLUTION
Therefore, our solution lies in Section 3, that is all values of x greater than 6, {x | x > 6}
Jackie V.
Thank you so much! This was major help!05/02/19