The reciprocal of a number can be represented as 1/x
The reciprocal of 2 less than the number can be represented as: 1/(x - 2)
Put them together (1/x) - (1/(x - 2)) = (-2/15)
Find a common denominator for all three terms by multiplying them all: x*(x-2)*15 and what you do to the bottom you must do to the top:
Thus: (1/x) multiply by (x-2) and 15 on the top and bottom to get [15(x-2)]/[x(x-2)(15)]
(1/(x-2)) multiply by x and 15 to get [15x/[x(x-2]15)
-2/15 multiply by x-2 and x to get [-2(x-2)(x)/(x(x-2)15]
All the denominators are now the same so they cancel out and you're left with the numerators
15(x-2) - 15x = -2(x-2)(x)
Distribute the values to get: 15x - 30 - 15x = -2x^2 +4x
Rearrange the values to get the problem equal to 0
-30 = -2x^2 +4x
2x^2 - 4x - 30 = 0
You can simplify by dividing all the terms by a common factor: 2
x^2 - 2x - 15 = 0
Then you can solve for x by factoring: find two numbers that add up to -2 and multiply to -15
Make a list and the two numbers end up being -5 and +3( see - 5 + 3 = -2 AND -5*3 = -15)
(x - 5)(x+3) = 0
T- off and set each equation in bubbles to 0 and solve for x
x - 5 = 0, so x = 5 AND x+ 3 = 0, so x = -3
Michael B.
Thank you!! It did a lot!!05/01/19