The sum of three consecutive odd integers is 63. Find the integers

Answer 1

Greetings! Lets solve this shall we ?

Let the first three consecutive integers be

x

(x+2)

(x+4)

Then the sum of these integers are

x + (x+2) + (x+4) = 63...................Now we begin solving for x such that

3x + 6 = 63...............Subtract 6 from both sides

3x = 57...............Then divide 3 such that

x = 19.............Since this is the first integer, then the second and third are

(19+2) = 21

(19+4) = 23

I hope this helped!