Given the geometric sequence-3, x, y, 192, ..., find the values of x and y.

Answer 1

Geometric sequence: k*r^n

k*R^1 = 3 ---> k*R = 3

k*R^4 = 192

(k*R)*r^3 = 192

3 * r^3 = 192

r^3 = 64

r = 4

that forces k= (3/4)

The geometric sequence is f(n) = (3/4)*4^n

n f(n)

1 3

2 12 <--- there;s the x

3 48 <--- there;s the y

4 192

5 768