First, you must know whether a zero in the left most digit is allowed or not.
I will assume that it is allowed.
There are 5! ways to form a 4 digit number with the 5 numbers.
Of those 4! end in 0 and 4! end in 5, i.e. are divisible by 5
Required probability = (4! + 4!)/5! = 48/120=48/120=2/5.