The sum of the first and third of three consecutive even integers is 160. Find the three even integers.

Answer 1

Greetings! Lets solve this shall we ?

Let the first and third even consecutive integers be equal to

1st = x

3rd = (x+4)

The sum of these must equal 160. Lets find these integers! So

x + (x+4) = 160..............Add like terms

2x + 4 = 160.................Subtract 4 to both sides

2x = 156......................Divide 2 to both sides

x = 78

So, the

1st integer is 78 and the third integer is (78+4) = 82!

I hope this helped!

Answer 2

Hi Rebecca!

Let's assign the first even number the letter 'n'

Since the second is also even, it is n+2

The third consecutive integer would be n+4

The first and third numbers would be n + n+4 and they both equal 160

Thus the equation, 2n + 4 = 160

Subtract 4 on both sides and divide 156 by 2, which equals 78

The even numbers sequence consecutively are: 78, 80, 82