
Steve M. answered 04/23/19
Majored in mathematics in college
Draw a side view. Using similar triangles, it is easy to see that if the smaller cone has radius r and height h, then
r = 3/5 (9-h)
or,
h = 5/3 (9-r)
The volume of the small cone is thus
v = π/3 r2h = 5π/9 r2(9-r)
dv/dr = 5π/3 r(6-r)
So, the maximum volume occurs when r=6 and h=5
That means that the maximum volume is 60π
The volume of the large cone is 405π
The smaller cone is 1/3 as tall, with 2/3 the radius, so its volume will be 1/3 * (2/3)^2 = 4/27 the larger volume, or 60π