If 13 liters of nitrogen gas went into the reaction and hydrogen was unlimited, how many grams of ammonia were produced?

Answer 1

The reaction referred to is N₂(g) + 3H₂(g) ===> 2NH₃(g)

We will assume this reaction takes place at STP (standard temperature and pressure) since these variables aren't stated in the question. And the volume of 13 liters can represent a different number of moles depending on the temperature and the pressure.

At STP, 13 liters x 1 mole/22.4 liters = 0.58 moles of N₂ gas

0.58 moles N₂ x 2 moles NH₃/ 1 mole N₂ x 17 g NH₃/mole NH₃ = 19.7 g = 20. g of NH₃ produced