Russ P. answered • 12/02/14
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Fred,
I don't know anything about water drops and you didn't supply any numerical definition of a drop. So I'll just compute g/sec instead.
25 gal/week = 25 gal (1/168 weeks/hour) (1/3600 hours/sec) = 4.1336 x 10-5 gallons/sec.
You figure out the drops.
Since you say 1ml = 1 drop and I U.S. gallon = 3785.4 ml
Answer: 25 gal/week = 4.1336 x 10-5 (3785.4 ml/gal) = 0.01565 (ml or drops)/sec
Russ P.
Since you say a drop is a ml, the problem should have just asked for the answer in ml. Anyhow,
1 U.S. Gallon = 3785.4 ml or now 3785.4 drops.
Therefore, 25 U.S. gallons/week = 4.1336 x 10-5 gal/sec (3785.4 drops/gal) = 0.01565 (ml or drops)/sec.
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12/02/14
Matt H.
I think 20 drops is ONE mL, based on my Googling. :-) I also find that 1 gallon therefore contains 90,921.8 drops... so...
Take Russ's number, multiply it by the above, and you should have your answer.
Question: is this for a math problem or for actual tank maintenance? If the latter, there MUST be a more sensible rate to use!
Good luck,
Matt in NY
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12/02/14
Fred M.
It is an actual system that I am setting up. What do you mean "a more sensible rate to use"? I am trying to effectively change roughly 10% per week without syphoning/refilling with buckets. Plus doing it this way creates more stable water parameters without major fluctuations that will shock and stress the inhabitants there in. and in my earlier post it should have said 20 drops = 1 ml.
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12/02/14
Fred M.
Here is where I fount 1ml = 20 drops
http://www.versaquatics.com/measurementconversion.htm
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12/02/14
Fred M.
12/02/14