Rebekah G. answered 03/14/13
Writing & Algebra I are my favorites!!!
The way you will set this question up is key. This will be a substitution formula and there will be two equations.
Let C equal the number of children and A equal the number of adults.
The two equations are:
A + C = 285 {the number of adults + the number of children = the number of people}
A(6.80) + C(2.00) = 1458 {the number of adults times the price of adults + the number of children times the price of children = the total admission fees}
I think it's easiest to rearrange the first equation and substitute it into the second equation. Subtract C from both sides of the first equation and you have A = 285 - C. Substitute this new sentence into the second one, since there will only be one term in it.
(285 - C)(6.80) + C(2.00) = 1458 {we put the first equation in for A}
1938 - C(6.80) + C(2.00) = 1458 {we multiplied (285 -C) by 6.80}
1938 - C(4.80) = 1458 {we simplified the C term}
- C(4.80) = -480 {we subtracted 1938 from both sides}
C(4.80) = 480 {multiplied both sides by -1}
C = 100 {divided both sides by 4.80)
Now we take our answer for C and go back to our first equation to solve for A
A + C = 285
A + 100 + 285 {put in value of C}
A = 185 {subtracted 100 from both sides}
Number of children = 100 & the number of adults = 185
You can check your work by plugging your values for A & C into the second equation
185(6.80) + 100(2.00) = 1458
1258 + 200 = 1458
Correct! :)