(-8,3), (-9,-2) in Ax+By=C

Question

Find an equation of the line passing through points (-8,3) and (-9,-2) and write the form in Ax + By = C

Answer 1

Given the two points (-8,3) and (-9,-2), we can generate the line which pass through them both...

y = mx + b

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Solving for m --> (-2 - 3)/(-9 - -8) = -5/(-1) = 5 (as the slope)

Solving for the y intercept gives --> b = y - mx --> 3 - 5(-8) = 43

Verifying the points...

3 = 5(-8) + 43 [ true ]

-2 = 5(-9) + 43 [ true ]

Therefore --> -mx + y = b is the format we will have which is required...

-5x + y = 43

A = -5, B = 1, C = 43