Math perimeter word problem.

Question

The area of each of 2 rectangles is 72 sq cm. The lengths and widths of each rectangle are integers. Rectangle 2's length is 5 cm greater than rectangle 1's length; rectangle 2’s width is 15 cm less than rectangle 1. What is the positive difference in the perimeters of rectangle 1 and rectangle 2?

Answer 1

L2 = L1 + 5

W2 = W1 - 15

P1= 2(L1 + W1)

P2 = 2(L2 + W2) = 2(L1 +5 + W1 - 15) = 2(L1 + W1) -20

P1 - P2 = 2(L1 + W1) - [2(L1 + W1) - 20] = 20