
Stephen H. answered 11/29/14
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AP Calculus AB/BC, GED & more - M.Ed. w/ 10+ yrs of experience
One method for finding a maximum or minimum is putting the quadratic in vertex form. To do so, one must complete the square. This process has the following steps:
1) factor a constant out of your x-terms
2) divide the 2nd term in the parenthesis by 2, square it and add it in the parentheses
3) multiply that value by your constant and subtract it at the end
The result should be in the form of y=a(x-h)^2+k
With the max/min at (h, k)
y = -16x^2 + 200x +4
y = -16(x^2 - 12.5x) + 4
y = -16(x^2 - 12.5x + 39.0625) + 4 -(39.0625•-16)
y = -16(x - 6.25)^2+629
The vertex if this parabola is (6.25, 629) so the maximum height of the arrow is 629 ft