Solve: 27^(4x) = 9^(x+1)

Answer 1

Hi Amy,

to solve this type of question, you will need to find a common base for both sides of the equation

as one of the number is 27 and the other is 9, the common base will be 3

27^(4x) = (3^3)^(4x) = 3^(12x)

9^(x+1) = (3^2)^(x+1) = 3^(2(x+1))

now you will have 12x = 2(x+1), and you can solve for x

Please let me know if you have any questions