The width of a rectangle is 5 feet more than length and the area is 66ft determine the deminsions of the rectangle

Question

A)Variable representation

B)equation and solution

C)answer to the problem

Answer 1

Area = Length x Width = lw

Width = l + 5

Area = 66 square feet

Area = 66 = l(l + 5)

66 = l² + 5l

A quadratic can be applied here

0 = l² + 5l - 66

Factoring

(l + 11)(l - 6) =0

l cannot be -11

l = 6

Width = l + 5 = 6 + 5 = 11

The rectangle has a length of 6 feet and a Width of 11 feet.