J.R. S. answered 04/06/19
Ph.D. University Professor with 10+ years Tutoring Experience
There will be heat transferred form the hot metal (iron) to the cold metal (gold). In order to answer this question, one needs to know the specific heats of both metals. Then use q = mC∆T where q is heat, m is mass, C is specific heat and ∆T is the change in temperature. So, you will have the following...
-miron x Ciron x Tf-55.6 = mgold x Cgold x Tf-18.0
-(30.0 g)(Ciron)(Tf-55.6) = (10.0 g )(Cgold)(Tf-18.0)j
Look up the specific heat (C) for iron and for gold, and substitute them in the above equation and solve for Tf which will be the final temperature of both metals.