(a) The perimeter of a rectangular field is 328m. If the length of the field is 95m, what is it's width?

Question

(b) The area of a rectangular painting is 8148 cm^2. If the width of the painting is 84 cm, what is it's length?

Answer 1

(a): The perimeter of a rectangle is 2L + 2W where "L" is the Length and "W" is the Width of the rectangle.

If the perimeter of the rectangle is 328m, you can write the following equation:

2L + 2W = 328.

Since you know the Length is 95m, you can substitute 95 in for L as follows:

2*95 + 2W =328

And you can solve as follows:

190 + 2W = 328

(Subtract 190 from both sides)

2W = 138

(Divide by 2)

W = 69

(b): The area of a rectangle is L * W

In this problem you know that the area is 8148, so you can write the following equation:

L * W = 8148

Since you know the Width is 84, you can substitute 84 in for W as follows:

L * 84 = 8148

(divide both sides by 84)

L = 97