Let L = length and W = width
Area = LW
L = W + 4
32 = W(W+4) =W2 + 4W
W2 + 4W - 32 = 0
This factors easily; one root is extraneous.
Alexandro M.
asked • 04/04/19The length of a small rectangular room is 4 units more than the width, and the area of the room is 32 square units. What are the dimensions of the room?
The length of a small rectangular room is 4 units more than the width, and the area of the room is 32 square units. What are the dimensions of the room?
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