What is the probability of picking a odd number and then picking another odd number if the numbers are 6 7 8 and 9

Question

I need answer fast and simplified please

Answer 1

This is compound probability. You find the answer by taking each individual probability and multiplying them by each other. The answer to your problem depends on what happens after picking the first number. The common terminology in math is replacing or not replacing.

For example, if you choose the odd number on the first pick the probability is 2/4 OR 1/2. If you replace the number you still have all 4 numbers. The probability of choosing an odd number the second time is the same, 1/2. As described earlier you multiply each probability by each other. P(odd number) x P(odd number): 1/2 * 1/2 = 1/4. The answer when replacing the original number is 1/4

Without replacing after the first drawn number your final answer looks different. The first draw remains the same, 2/4 OR 1/2. If you hold on to that number, the probability of drawing another odd number is 1/3 because there is only 1 odd number left and there is a total of 3 numbers remaining. You take 1/2 * 1/3 = 1/6. The answer without replacing after the first draw is 1/6

Answer 2

I tried to record a video answer, but it never processed. Here is an image of the final result: https://www.dropbox.com/s/1wpr0bq0k09bczn/Probability%20Odd%20Number.PNG?dl=0