Dn = 3 + 4n for n≥0
Nn = 7 + 4n for n≥0
an = (4n + 7)/(4n + 3) = [4 + (7/n)]/[4 + (3/n)] for n>0
thus lim as n->∞ an = 1 and therefore, the series cannot converge.
In order for an infinite series (sum) to converge the sequence which forms the series must converge to 0.