Hadi B. answered 04/02/19
BS in Mathematics with 5+ years of tutoring experience
we can set up a system of equations
let p be the number of pennies, n be the number of nickels, and d be the number of dimes
we have $2.03 in change, so we have 2.03 = .01p + .05n + .10d
we also know d = 2n and p = 2d
so, we can use these to substitute into the equation and solve for d
2.03 = .01p + .05n + .10d
2.03 = .01(2d) + .05(.5d) + .10d
2.03 = .02d + .025d + .10d
2.03 = .145d
14 = d
then 14 = 2n, so n = 7
and p = 2(14) = 28