What’s the equation of a line in slope intercept form of a line that is the line 3x-5y+15=0 ans passes through the point P(-4,6)

Answer 1

The given line: 3x - 5y + 15 = 0

All parallel lines: 3x - 5y + C = 0 and we need the point (-4,6) to determine C:

3(-4) -5(6) + C = 0

-12 -30 + C = 0

C = 42

The parallel line is: 3x - 5y + 42 = 0

All perpendicular lines have a formula that looks like: 5x + 3y + C = 0 and we need to find C:

5(-4) + 3(6) + C = 0

-20 + 18 + C = 0

C = 2

The perpendicular line is: 5x + 3y + 2 = 0

Answer 2

Don"t understand the question. Sure it's copied correctly?

Jim