
Hadi B. answered 03/27/19
Tutor
5.0
(121)
BS in Mathematics with 5+ years of tutoring experience
Let x be the first number, then x+1 is the second number
Then we can set up the equation
x2+(x+1)2=41
Multiply and solve for x
x2+x2+2x+1=41
2x2+2x-40=0
x2+x-20=0
(x-4)(x+5)=0
So, x=4 or x =-5
So, the consecutive negative integers are -5 and -4