A farmer bought a number of pigs for $280. However, 4 of them died before he could sell the rest at a profit of 6 per pigs. His total profit was $104. How many pigs did he originally buy?

Answer 1

Let X stand for number of pigs

Four pigs died. We can represent that algebraically as X - 4

Since the price per pig is $6

His total profit was $104, so he acquired $384

The equation then becomes 6(X-4) = 384

Solving for X:

6x - 24 = 384

6x = 408

X = 68 pigs

Answer 2

Let x represent the number of pigs the farmer bought

If 4 died he is left with (x-4) pigs

For home to make a profit of $104 he would have had to sold the pigs for $384.( original cost of 280 + profit of 104 )

So 6(x-4)= 384

6x -24=384

6x= 408

x=68

Answer 3

Let n= the number of pigs purchased.

Let p = price paid for the pigs.

So np = 280

The farmer sold (n-4) pigs for (p + 6) for a total of 384

So (n-4)(p +6)=384

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