consider the following quadratic equation

Question

-4x^2 +bx-11=0

Determine a possible value of b so that the quadratic has two complex solutions.

A.)14

B.)-16

C.)-14

D.)12

Answer 1

For a quadratic equation to have no real solutions the determinant (b^2 -4ac) must be <0.

In this equation a=-4, b is unknown and c=-11

so b^2 -(4)(-4)(-11) <0

b^2 -176<0

b^2<176

The only choice that works is 12