What's maximum height, how long, and until it reaches bottom
what is the maximum height the ball reaches? how long will it take the baseball to reach the maximum height? how long does it take for it to reach the ground?
-16t^2+100t+25
h(t) = -16t2 +100t + 25 ft
Ball reaches its maximum height when h'(t) = 0.
h'(t) = -16•2t + 100 = -32t + 100
-32t + 100 = 0
32t = 100
t = 3.125 s
hmax = -16•(3.125)2 + 100•3.125 + 25
hmax = 181.25 ft
Ball reaches ground when h(t) = 0.
h(t) = 0 = -16t2 +100t + 25
Factoring the quadratic by completing the square...
-16t2 +100t + 25 = 0
t2 − (100/16)t − (25/16) = 0
t2 − (100/16)t − (25/16) = 0
t2 − (25/4)t − (25/16) = 0
t2 − (25/4)t = (25/16)
t2 − (25/4)t + (−25/8)2 = (25/16) + (625/64)
[t − (25/8)]2 = (100/64) + (625/64)
√{[t − (25/8)]2}= √(725/64)
t − (25/8) = (5/8)•√29
t = (25/8) + (5/8)•√29
t ≈ 6.49 s

Ron G.
Nice layout there. Question: what do you think of Wolfram Alpha as a problem-solver tool?03/22/19