Set to zero and factor (3n+1)(n-3)=0
So solutions are
3n+1=0. n-3=0
3n=-1. n=3
n=(-1/3)
Set to zero and factor (3n+1)(n-3)=0
So solutions are
3n+1=0. n-3=0
3n=-1. n=3
n=(-1/3)
This expression factors as (n-3)(3n+1)
When you set each equal to zero,
you get
n-3 = 0 so n=3
3n + 1 = 0 so n = -1/3
The two solutions are
3, -1/3
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