How do you express sqrt(3) in polar form?

Answer 1

Hey! Are you sure it is asking for polar form? If yes, then

square root of 3 comes from tangent 60 degrees from the Unit Circle where

tan60 = (root(3)/2) / (1/2) = (root(3) / 2) * (2/1) = root(3).

The degree form of tangent is y/x = sin(θ)/cos(θ) = tanθ.

Hence, r(θ) = atanθ is the polar form, where a is the coefficient of revolutions around the Unit Circle.

Hope this helps!