What's the equation of a line passing through the point (-4, 2) & having a slope of 1/2

Answer 1

B = y - mx

= 2 - (1/2)(-4)

= 2 - -2

= 4

y = (1/2)x + 4

Answer 2

There are two different equations we can use to answer this problem. The slope-intercept form y = mx + b or the point-slope form y- y₁ = m ( x - x₁). In both of these equations, m represents the slope and ( x₁ , y₁ ) is any point on the line.

Let's work with y = mx + b first.

We have the point (-4, 2) so we can plug -4 in for the x in our equation, and 2 in for the y. We also know that the slope is 1/2, so m = 1/2

y = mx + b

2 = 1/2 (-4) + b We want to get b by itself, so first multiply the 1/2 and -4 to get -2

2 = -2 + b Add 2 to both sides to cancel the -2 by the b

4 = b

Now, we can plug m = 1/2 and b = 4 into our original equation to get the equation of the line.

y = 1/2 x + 4 Final answer!

Now let's try it using the point-slope form of the equation, y - y₁ = m ( x - x₁)

We have the point ( -4 , 2 ) so x₁ = -4 and y₁ = 2. The slope is still 1/2 so m = 1/2.

y - y₁ = m ( x - x₁ )

y - 2 = 1/2 ( x- (-4) ) x - (-4) can be written as x+4

y - 2 = 1/2 ( x + 4) Now distribute the 1/2 by multiplying it to both the x and the 4

y- 2 = 1/2 x + 2 We want to get the y by itself, so add 2 to both sides of the equation

y = 1/2 x +4 Final answer!

Answer 3

Your given point is (-4,2). So:

2= (1/2)(-4) + c ------> 2= -2 + c ----> c= 4

y= 1/2 x + 4