J.R. S. answered 03/17/19
Ph.D. University Professor with 10+ years Tutoring Experience
Cl2 + 3F2 ==> 2ClF3 (note: chlorine trifluoride is ClF3, not ClF2)
For Cl2: 1.75/1 = 1.75
For F2: 8.68/3 = 2.89
Cl2 is limiting
mass ClF3 = 1.75 mol Cl2 x 2 mol ClF3/mol Cl2 x mokar mass ClF3 = answer in grams
Since Cl2 is limiting, F2 is in xs
moles F2 present - 3x1.75 = moles F2 remaining
moles F2 remaining x mokar mass F2 = mass F2 remaining