J.R. S. answered 03/17/19
a.). CuO(s) + H2(g) ==> H2O + Cu
b.). 19.9 g CuO x 1 mol CuO/79.5 g x 1 mol Cu/mol CuO x 63.5 g Cu/mol Cu = 15.9 g Cu
2.02 g H2 x 1 mol/2 g x 1 mol Cu/mol H2 x 63.5 g Cu/ mol Cu = 128 g Cu
Since Cu is limiting, only 15.9 g Cu will form.