Greg D. answered 11/18/14
Tutor
New to Wyzant
Pre-Algebra, Algebra, Geometry, College Algebra, Vocational Math
Hey Annie!
You could do it this way too.
This is a THERE and BACK problem.
Let x represent the distance between points A and B.
Make a Chart.
Column #1 would be the RATE column
Column #2 would be the TIME column
Column #3 would be the DISTANCE column
Row #1 would be the THERE row
Row #2 would be the BACK row
So the chart would look like this:
RATE TIME DISTANCE
THERE 10 x
BACK 6 x
To fill in the TIME column just divide the DISTANCE by the RATE
So the chart would now look like this:
RATE TIME DISTANCE
THERE 10 x/10 x
BACK 6 x/6 x
THERE 10 x/10 x
BACK 6 x/6 x
The equation will come from the TIME column.
Time THERE plus Time BACK equals 1.6 hours ( 1 hour and 36 minutes = 1.6 hours )
So, x/10 + x/6 = 1.6
Solve this equation by multiplying each term on both sides by 60.
So the equation becomes 6x + 10x = 96
Solve the equation and x = 6
Which is the distance between the point A and B, 6 miles !
Happy days.