In the following graph of F(x) = -(2/3)(x-3)2 + 2 is the preimage of a transformation of G(x)which is the image. What is the mapping statement for the function G(x)?

Question

In the following graph of F(x) = -(2/3)(x-3)² + 2 is the preimage of a transformation of G(x)which is the image. What is the mapping statement for the function G(x)?

(I'm not sure how to make a mapping statement for this function)

Answer 1

F(x) has been moved down 1 unit and left 4 units.

G(x) = (-2/3)(x-3(+4))^2 +2 -1 The +4 moves the graph 4 units to the left, and the -1 moves it down 1

So you now have G(x) = -(2/3)(x+1)^2 + 1

Patti D.