The sum of two numbers is 11. The second number is 1 less than twice the first number. Find the two numbers.

Question

What are the two numbers?

Answer 1

x + y = 11

y = 2x - 1

x + (2x - 1) = 11

x + 2x - 1 = 11

3x - 1 = 11

3x = 11 + 1

3x = 12

x = 4

(4) + y + 11

4 + y = 11

y = 11- 4

y = 7

The numbers are 4 and 7.