Find an equation of the line passing through the point (5,4) and parallel to whose equation is 2x + y =3.

Question

A. y + 4= 2(x-5)

B. y - 4 = -2( x -5)

C. y + 4 = -2 (x +5)

D. y - 4 = 2( x + 5)

Answer 1

The equation of the given line in slope-intercept form is y=-2x+3

Therefore, the slope of the sought-after line parallel to this given line is -2..

Using the point-slope form of the equation of a line,

y-4=-2(x-5),

Further simplification of this gives y-4=-2x+10, which in slope-intercept form ends up as y=-2x+14.