the length of a rectangle is 5 yd longer than its width. If the perimeter of the rectangle is 66 yd, finds it length and width

Answer 1

From the definition of a rectangle, the perimeter is 2L + 2W, and you know the perimeter = 66 yards so we have one equation:

2L + 2W = 66

You know that the length is 5 yards more than the width, so you have a second equation:

L = W + 5

Substitute W + 5 into the first equation in place of L:

2(W+5) + 2W = 66

Work this out by distributing and combining like terms. Then use your answer for W to determine L. I think you can take it from here.

--Louise