An equation of a line that is parallel to y = -5/4 + 7 and that passes through the point -4,1

Answer 1

y = -5/4 + 7 has a slope of -5/4. The line parallel to it also has a slope of -5/4. Using the point-slope form of a line which is (y - y₁) = m(x - x₁) we can plug in the point (-4, 1) as (x₁, y₁) so the point-slope form becomes:

(y - 1) = -5/4(x + 4)

If you want to turn that into the slope-intercept form (y = mx + b), multiply it out and combine like terms to get:

y = -5/4x -4