one number added to three times another number is 24. five times the first number added to three times the other number is 36 find the numbers.

Answer 1

The 2 conditions are:

A + 3B = 24

5A + 3B = 36

subtract the first equation from the second to get. 4A = 12, So A = 3, then substitute to get B = 7.

Answer 2

x+3y = 24

5x+3y = 36

5(24 - 3y) + 3y = 36

120 - 15y + 3y = 36

120- 12y = 36

-12y = -84

y = -84/-12 = 7

x = 24 - 3(7) = 24 - 21 = 3

3 and 7