A line contains the point...

Question

A line contains the point (–3, –4) and is perpendicular to a line with a slope of . Write an equation of the line satisfying the given conditions. Write the answer in slope-intercept form. 

y=mx+b

Answer 1

Perpendicular lines have slopes that are negative reciprocals.

So the line has slope (-5/3)

The formula for the intercept is B = y - mx where (x,y) is a point on the line.

B = -4 - (-5/3)(-3)

= -4 - (5)

= -9

the equation is y = (-5/3)x + -9

Answer 2

y - (-4) = (-5/3)(x - (-3))

y + 4 = (-5/3)x - 5

y= (-5/3)x - 9