Patrick B. answered 03/07/19
Math and computer tutor/teacher
1,3,6,10,15,21,28,38,47,57
the difference between each term is 1 greater than the previous
since it is NOT a common difference, the sequence is not linear
f(1) = 1
f(2) = 3
f(n) = f(n-1) + f(n-1)-f(n-2)+1
= 2 * f(n-1) - f(n-2) + 1
So f(3) = 2 * f(2) - f(1) + 1 = 2 * 3 - 1 + 1 = 6
f(4) = 2 * f(3) - f(2) + 1 = 2 * 6 - 3 + 1 = 12 - 3 + 1 = 10
f(5) = 2 * f(4) - f(3) + 1 = 2 * 10 - 6 + 1 = 20 - 6 + 1 = 15