Doug C. answered • 03/05/19

Math Tutor with Reputation to make difficult concepts understandable

Adam, try this:

Solve by factoring out e^{x}.

e^{x}(2e^{x} -1)=0

So e^{x}=0 or 2e^{x}-1=0

The first can never equal zero. But for the 2nd e^{x} = 1/2. Take the natural log of both sides to isolate x. You will see that ln (.5) is the solution.