Don L. answered 04/08/19
Fifteen years teaching and tutoring basic math skills and algebra
Hi Danielle, use the equation, an = a1 * (r)n, to solve your problem. You will have to use it three times.
First equation:
a10 = 6
6 = a1 * (r)10
solve for a1:
a1 = 6 / (r)10
Second equation:
a30 = 36
36 = a1 * (r)30
Solve for a1:
a1 = 36 / (r)30
Since a1 from the first equation must equal a1 from the second equation, we can equate a1 to a1, or,
6 / (r)10 = 36 / (r)36
Cross multiply:
r36 / r10 = 36 / 6
r20 = 36
r = 1.0937
Knowing r, you can find a1, using either the first or second equation:
Using the first equation, substitute for an, 6, and r, 1.0937:
6 = a1 * (1.0937)10
a1 = 6 / (1.0937)10
a1 = 2.45
Third equation:
Substitute for a1, 2.45, r, 1.0937, and n, 40
a40 = 2.45 * (1.0937)40
a40 = 88.12
I am not sure who you get partial bunnies, but the answer, rounded, is 88.
Questions?