The polynomial of degree 3 , P ( x ) , has a root of multiplicity 2 at x = 5 and a root of multiplicity 1 at x = − 5 . The y -intercept is y = − 50 .

Answer 1

P(x) = k(x-5)(x-5)(x-1) with P(0)=-50

Since the y-intercept is -50, that means (0,-50) is the

point on the y-axis where the polynomial crosses the y-axis;

x=0 when y=-50

-50 = k(-5)(-5)(-1)

-50 = -25k

k=2

P(x) = 2(x-5)(x-5)(x-1)