Kira J.
asked • 03/02/19I need help with my math.
Mariana averaged 80 on her first three history exams.The first score was 83. The second score was 3 less than the third score. What did she score on the second and third exams?
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1 Expert Answer
80 = (83 + t - 3 + t)/3
240 = 2t + 80
2t = 160
t = 80
s = 80 - 3
s = 77
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Ahmed D.
Let the first X The second Y The third Z (X+y+z)/3=80 X+y+z=240 "Since" X=83 "Then" y+z=240-83=157 -------------------- Writing the two equations Y+z=157 -y+z=3 "Adding the two equations" 2Z=160 Z=160/2=80 ================= Y=157-80=77 ==================== ==================== Then The first number 83 The second 77 The third 8003/02/19